Q. 40 A5.0( 2 Votes )

Solve the matrix

Answer :


Now we will multiply the two first matrices on LHS using the formula cij = ai1b1j + ai2b2j + … + ainbnj, we get




Again multiply these two LHS matrices, we get



x2 – 2x – 15 = 0. This is form of quadratic equation, we will solve this by splitting the middle term, we get


x2 – 5x + 3x – 15 = 0


x(x – 5) + 3(x – 5) = 0


(x – 5)(x + 3) = 0


x – 5 = 0 or x + 3 = 0


This gives, x = 5 or x = – 3 is the required solution of the matrices.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Prove the followiMathematics - Board Papers