Q. 40 A5.0( 1 Vote )

Solve the matrix equations:


Answer :


Now we will multiply the two first matrices on LHS using the formula cij = ai1b1j + ai2b2j + … + ainbnj, we get




Again multiply these two LHS matrices, we get



x2 – 2x – 15 = 0. This is form of quadratic equation, we will solve this by splitting the middle term, we get


x2 – 5x + 3x – 15 = 0


x(x – 5) + 3(x – 5) = 0


(x – 5)(x + 3) = 0


x – 5 = 0 or x + 3 = 0


This gives, x = 5 or x = – 3 is the required solution of the matrices.


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