Answer :

Given: and


To show that


Substitute in , we get



I is identity matrix, so


Now, we will find the matrix for A2, we get




[as cij = ai1b1j + ai2b2j + … + ainbnj]




Now, we will find the matrix for 2A, we get





Substitute corresponding values from eqn(ii) and (iii) in eqn(i), we get





[as rij = aij + bij + cij],



So,


Hence Proved


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