Q. 34.4( 10 Votes )

# Find the square o

Answer :

Using the identity (a + b)^{2} = a^{2} + b^{2} + 2ab

Here, 72^{2} = (1465 + 3)^{2}

= 1465^{2} + 3^{2} + 2×1465×3 ..(i)

Since 1465 terminates with 5,

1465^{2}⇒ 146 × (146 + 1)

= 146 × 147

= 21462

1465^{2} = 2146225

Substituting 1465^{2} in equation (i)

= 1465^{2} + 3^{2} + 2×1465×3

= 2146225 + 9 + 8790

= 2155024

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