Q. 1 A4.2( 5 Votes )

# Find the sum of t

The arithmetic progression 1, 3, 5, 7, …. is given.
Here first term is 1 and common difference is 3 – 1 = 2.
Since the sum of n terms is
Sn = Where,

a = First term of AP
d = Common difference of AP
and no of terms is ‘n’

So sum of first 12 terms S12 = 6[ 2 + 11×2]
= 6[2 + 22]
= 6 × 24
= 144

Hence, Sum of first 12 terms is 144.

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