Q. 123.8( 12 Votes )

A ball is thrown vertically upward from the top of a building 96m tall with an initial velocity 80m/second. The distances of the ball from the ground after t seconds is s = 96 + 80t - 4.9t². After how may seconds does the ball strike the ground.

Class 10th AP- Mathematics 5. Quadratic Equations

Answer :

s = 96 + 80t - 4.9t²

When the ball reaches the ground, s = 0

4.9t² - 80t - 96 = 0

Since time cannot be negative so negative root is neglected

⇒ Time taken = 17.44 s

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