Q. 105.0( 9 Votes )
In the Fig. 5.10, we have AC = DC, CB = CE. Show that AB = DE.
Given: AC =DC …(i)
and CB = CE …(ii)
According to Euclid’s axiom, if equals are added to equals, then wholes are also equal.
So, on adding Eq.(i) and (ii),
AC + CB = DC + CE
⇒ AB = DE
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In the given figure, it is given that AC=BD,
Prove that AB=CD.
RS Aggarwal & V Aggarwal - Mathematics