# Find the sum of the following APs:(i) 2, 7, 12, . . ., to 10 terms.(ii) –37, –33, –29, . . ., to 12 terms.(iii) 0.6, 1.7, 2.8, . . ., to 100 terms.(iv) (i) Here, a = 2, d = 5 and n = 10

Sum of n terms can be given as follows: S10 = 5(4 + 45)

= 5 = 245

Thus, sum of the 10 terms of given AP (Sn)=245

(ii) Here, a = - 37, d = 4 and n = 12

Sum of n terms can be given as follows: S12 = 6(-74 + 44)

= 6 =-180

Thus, sum of the 12 terms of given AP (Sn)= -180

(iii) Here, a = 0.6, d = 1.1 and n = 100

Sum of n terms can be given as follows: S100 = 50(1.2 + 108.9)

= 50 =5505

Thus, sum of the 100 terms of given AP (S100) = 5505

(iv) Here,

a= , n = 11,

d = Sum of n terms can be given as follows: S11 = ( + )

= = Thus, sum of the 100 terms of given AP (Sn)= Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Champ Quiz | Arithmetic Progression34 mins  Smart Revision | Arithmetic Progression47 mins  Champ Quiz | Arithmetic Progression30 mins  Quiz | Arithmetic Progression44 mins  Smart Revision | General Term of an A.P44 mins  NCERT | Fundamental Theorem Of Arithmetic45 mins  Lets Check Your Knowledge in A.P.49 mins  Quiz on Arithmetic Progression Quiz32 mins  NCERT | Arithmetic Progression36 mins  Fundamental Theorem of Arithmetic- 143 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 