# Find the sum of a

Formula used.

Sn = [a + l]

an = a + (n–1)d

The 1st odd number is 5

The last odd number is 205

Difference between every odd number is 2

an = a + (n–1)d

205 = 5 + (n–1)2

205 = 5–2 + 2n

2n = 205 – 3

n = = 101

Sn = [a + l]

= [5 + 205]

= 101×105

= 10605

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