Answer :

Put n = 1, 2, 3, 4

We get

a_{1} = 2(1) - 3 = - 1

a_{2} = 2(2) - 3 = 1

a_{3} = 2(3) - 3 = 3

a_{4} = 2(4) - 3 = 5

List of AP is - 1, 1, 3, 5 . . . .

a_{2} - a_{1} = 1 - (- 1) = 2

a_{3} - a_{2} = 3 - 1 = 2

a_{4} - a_{3} = 5 - 3 = 2

which form an AP, with common difference , d = 2

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