Answer :

Put n = 1, 2, 3, 4


We get


a1 = 2(1) - 3 = - 1


a2 = 2(2) - 3 = 1


a3 = 2(3) - 3 = 3


a4 = 2(4) - 3 = 5


List of AP is - 1, 1, 3, 5 . . . .


a2 - a1 = 1 - (- 1) = 2


a3 - a2 = 3 - 1 = 2


a4 - a3 = 5 - 3 = 2


which form an AP, with common difference , d = 2


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