Answer :

Here last term of the progression l = -62.
First term a = 10 and common difference = 7 – 10 = -3
We know, In an AP, the nth term from last is


an = l – (n – 1)d


where an is nth term from last, l is last term and ‘d’ is common difference.


Thus 11th term from the end
= l – (11 -1)d
= -62 – (10) × (-3)
= -62 + 30
= -32


Hence, 11th term from the last is -32.


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