Answer :

Let A(h,0) B(am) and C (0, k) are the three points


Since the three points A(h,0) B (a, b) and C (0, k) lie on a straight line we can say that the three points are collinear.


So, area of triangle ABC = 0


Area of triangle =


x1 = h, x2 = a and x3 = 0


y1 = 0, y2 = b and y3 = k





0 = hb + ak kh


hab + ak = kh


Divided by (kh) on both sides we get




Hence proved.


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