Q. 65.0( 1 Vote )

# If the three poin

Answer :

Let A(h,0) B(am) and C (0, k) are the three points

Since the three points A(h,0) B (a, b) and C (0, k) lie on a straight line we can say that the three points are collinear.

So, area of triangle ABC = 0

Area of triangle =

x1 = h, x2 = a and x3 = 0

y1 = 0, y2 = b and y3 = k

0 = hb + ak kh

hab + ak = kh

Divided by (kh) on both sides we get

Hence proved.

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