Answer :

Let A(h,0) B(am) and C (0, k) are the three points

Since the three points A(h,0) B (a, b) and C (0, k) lie on a straight line we can say that the three points are collinear.

So, area of triangle ABC = 0

Area of triangle =

x_{1} = h, x_{2} = a and x_{3} = 0

y_{1} = 0, y_{2} = b and y_{3} = k

⇒

⇒

⇒

⇒ 0 = hb + ak – kh

⇒ hab + ak = kh

Divided by (kh) on both sides we get

⇒

⇒

Hence proved.

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