Answer :

Smallest 3-digit number that is divisible by 7 is 105 and greatest 3-digit number that is divisible by 7 is 994.
Let the no. of three digits numbers that are divisible by 7 be n.


Thus, an = 994, first term a = 105 and common difference d = 7.


Since, an = a + (n - 1)d


Where,


a = First term of AP
d = Common difference of AP
and no of terms is ‘n’



994 = 105 + (n - 1) × 7
994 – 105 = 7 × (n - 1)
889 = 7 × (n - 1)
127 = n – 1
n = 128


Hence, Total 3-digit numbers that are divisible by 7 are 128.


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