Answer :

Formula used:


(a, 0), (–a, 0) and (0, a√3)


Let the points be A (a, 0), B (–a, 0) and C (0, a√3)


Distance of AB


AB = √ ((–a – a)2 + (0 – 0)2)


AB = √ ((–2a)2 + (0)2)


AB = √ (4a2 + 0)


AB = √4a2


AB = 2a


Distance of BC


B C= √ ((0 – a)2 + (a√3 – 0)2)


BC = √ ((–a)2 + (a√3)2)


BC = √ (a2 + 3a2)


BC = √4a2


BC = 2a


Distance of AC


AC = √ ((0 – a)2 + (a√3 – 0))2)


AC = √ ((–a)2 + (a√3)2)


AC = √ (a2 + 3a2)


AC = √ 4a2


AC = 2a


AB = BC = AC = 2a


Since, all the sides are equal the points form an equilateral triangle.


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