Q. 5 B5.0( 1 Vote )

# Find the area of

When the vertices of a quadrilateral is given then its area is given by {(x1–x3)(y2–y4) – (x2–x4)(y1–y3)}

We must take all the vertices in counter clock wise direction otherwise it will give solution in negative.

So, from the figure we assume that

A (x1, y1) = (4, –1)

B (x2, y2) = (1, 2)

C (x3, y3) = (–3, 4)

D (x4, y4) = (–5, –6) The area of the quadrilateral is {(x1–x3)(y2–y4) – (x2–x4)(y1–y3)}

= {(4–(–3))(2–(–6)) –(–1–4)(1–(–5))}

= {56+30} = 43 Sq. units

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