(k, k) (2, 3) and (4, –1)Area of triangle = x1 = k, x2 = 2 and x3 = 4y1 = k, y2 = 3 and y3 = –1⇒ ⇒ ⇒ ⇒ 7k – 2 – k – 12 = 0⇒ 6k – 14 = 0⇒ 6k = 14⇒

Q. 4 C5.0( 1 Vote )

In each of the fo

Answer :

(k, k) (2, 3) and (4, –1)

Area of triangle =

x₁ = k, x₂ = 2 and x₃ = 4

y₁ = k, y₂ = 3 and y₃ = –1

⇒

⇒ 7k – 2 – k – 12 = 0

⇒ 6k – 14 = 0

⇒ 6k = 14

⇒

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