Q. 3 E3.7( 3 Votes )

# For a given A.P.

Answer :

Formula used.

Sn = [2a + (n–1)d]

S10 = 50

n = 10

a = 0.5S10 = [2×0.5 + (10–1)d]

50 = 5[1 + 9d] = 1 + 9d

9d = 10–1

d = = 1

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