Answer :

Formula used:


(–2, 0), (4,0) and (1, 3)


Let the point be A (1, 3) B (–2, 0) and C (4, 0)


Distance of AB


AB = √ ((–2 – 1)2 + (0 – 3)2)


AB = √ ((–3)2 + (–3)2)


AB = √ (9 + 9)


AB = √ 18 = 3√ 2


Distance of AC


AC = √ ((4 – 1)2 + (0 – 3)2)


AC = √ ((3)2 + (–3)2)


AC = √ (9 + 9)


AC = √ 18 = 3√2


Distance of BC


BC = √ ((4 – (–2))2 + (0 – 0)2)


BC = √ ((6)2 + (0)2)


BC = √ (36 + 0)


BC = √ 36 = 6


We notice that AB = AC =3√2


Points A, B and C are coordinates of an isosceles triangle.


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