Answer :

Given: In ΔPQR, right-angled at Q, PQ = 3 cm and PR = 6 cm. 

To find: 

Solution:

Take right angle ΔPQR right angled at Q.

Since,

 

Here,





since,



So, sin R = sin 30°

⇒ R = 30°

Now, in ΔPQR

As sum of all angles of a triangle is 180°.

∠P = 180° - ( 90° + 30° )

∠P = 180° - 120° 

∠P = 60°

Hence the value of ∠R is  30° and ∠P is  60°.

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