# In a ΔABC, DE || BC, where D is a point on AB and E is a point on AC, then(i) =……… (ii) =………(iii) =……… (iv) =……… (i) Given: DE || BC

Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio. [by basic proportionality theorem]

(ii) Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.

By basic proportionality theorem, we know that      (iii) From part (i), we know that On adding 1 to both the sides, we get   (iv) From part (iii), we have  Rate this question :

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