# In figures (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).

(i)

Given: DE || BC

[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.]

[given: AD= 1.5cm, DB =3cm & AE =1cm]

EC = 2cm

(ii)

Given: DB = 7.2 cm, AE = 1.8 cm and EC = 5.4 cm

and DE || BC

[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.]

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