Answer :

The given arithmetic progression is 9, 13, 17, 21, …

Its first term a = 9

Common difference = d = 13 – 9 = 4.

So n^{th} term a_{n} of the given arithmetic progression is given by

a_{n} = a + (n -1)d

Where,

a = First term of AP

d = Common difference of AP

and no of terms is ‘n’

Thus 24^{th} term a_{24} = 9 + (24 - 1) × 4.

⇒ a_{24} = 9 + 23 × 4 = 9 + 92 = 101

Hence, 24^{th} term is 101.

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