Formula used.Sn = [2a + (n–1)d]d = an + 1–anIn the following A.Pa = 5,d = a2–a1= 7–5 = 2;n = 30Sn = [2a + (n–1)d]= [2×5 + (30–1)2]= 15[10 + 29×2]= 15[10 + 58]= 1020

Q. 1 B3.7( 3 Votes )

Find the sum of t

Class 10th Gujarat Board Mathematics 5. Arithmetic Progression

Answer :

Formula used.

S_n = [2a + (n–1)d]

d = a_{n + 1}–a_n

In the following A.P

a = 5,

d = a₂–a₁

= 7–5 = 2;

n = 30

S_n = [2a + (n–1)d]

= [2×5 + (30–1)2]

= 15[10 + 29×2]

= 15[10 + 58]

= 1020

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