SubbaRao started work in 1995 at an annual salary of Rs 5000 and received an increment of Rs 200 each year. In which year did his income reach Rs 7000?

Here, a = 5000, d = 200 and a_n = 7000

We know, a_n = a + (n – 1)d

7000 = 5000 + (n – 1)200

(n -1)200 = 7000 – 5000

(n – 1)200 = 2000

n – 1 = 10

n = 11

i.e. after 11 years, starting from 1995, his salary will reach to 7000, so we have to add 10 in 1995, because these numbers are in years.

Thus, 1995 + 10 = 2005

Hence, his salary reached at Rs. 7000 in 2005.