Answer :

Formula used:


Let the point A (0, –5), B (4, 3) and C (–4, –3) lie on the circle with center O (0, 0)


Distance of AO


AO = √ ((0 – 0)2 + (0 – (–5))2)


AO = √ ((0 – 0)2 + (0 + 5)2)


AO = √ ((0)2 + (5)2)


AO = √ (0 + 25)


AO = √ 25


AO = 5


Distance of BO


BO = √ ((0 – 4)2 + (0 – 3)2)


BO = √ ((–4)2 + (–3)2)


BO = √ (16 + 9)


BO = √ 25


BO = 5


Distance of CO


CO = √ ((0 – (–4))2 + (0 – (–3))2)


CO = √ ((0 + 4)2 + (0 + 3)2)


CO = √ ((4)2 + (3)2)


CO = √ (16 + 9)


CO = √ 25


CO = 5


AO = BO = CO = 5 = Radius


Hence, point A, B and C lie on the circle.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the distanceTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I

Show that the folTamilnadu Board Math Term-I