Answer :

Formula used:


Let the point be A (–5, 6) and O (3, 2)


Distance of OA


OA = √ ((–5 – 3)2 + (6 – 2)2)


OA = √ ((–8)2 + (4)2)


OA = √ (64 + 16)


OA = √ 80


OA = 4√5


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