Q. 13.6( 160 Votes )

# Find the modulus

Answer :

**Given:** z = –1 – i√ 3**Formulas: ****Modulus of a complex number z = x + i y is given by,**

|z| = √(x^{2} + y^{2})

So modulus of given z is,

|z| = √[(-1)^{2} + (√3)^{2}]

|z| = √4 = 2

Now for argument let us find out the quadrant in which the complex number is present.

As real and imaginary parts are negative, z lies in third quadrant.

Thus Argument of z in third quadrant is,

arg(z) = α - π

And where,

α = π/3

arg(z) = π/3 - π

= - 2π/3

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