Q. 85.0( 1 Vote )

# Which term of A.P

Formula Used.

dn = an + 1 – an

an = a + (n–1)d

In the above sequence,

a = 8;

d1 = a2–a1 = 11–8 = 3

d2 = a3–a2 = 14–11 = 3

d3 = a4–a3 = 17–14 = 3

The difference in sequence is same and comes to be (3).

For any term of A.P to be 272

an = a + (n–1)d = 272

an = a + (n–1)d = 8 + (n–1)(3)

= 8 + 3n–3

= 5 + 3n

5 + 3n = 272

3n = 272–5 = 267

n = = 89

The 89th term of A.P has value 272

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