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# Can any term of A

Formula Used.

dn = an + 1 – an

an = a + (n–1)d

In the above sequence,

a = 201;

d1 = a2–a1 = 197–201 = –4

d2 = a3–a2 = 193–197 = –4

The difference in sequence is same and comes to be (–4).

For any term of A.P to be 5

an = a + (n–1)d = 5

an = a + (n–1)d = 201 + (n–1)(–4)

5 = 201–4n + 4

5 = 205–4n

–4n = –205 + 5

n = = 50

The 50th term of A.P is 5

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