Answer :

Formula Used.


dn = an + 1 – an


an = a + (n–1)d


In the above sequence,


a = 12;


d1 = a2–a1 = 17–12 = 5


d2 = a3–a2 = 22–17 = 5


d3 = a4–a3 = 27–22 = 5


The difference in sequence is same and comes to be (5).


For any term of A.P to be 0


an = a + (n–1)d = 0


an = a + (n–1)d = 12 + (n–1)(5)


= 12 + 5n–5


= 7 + 5n


7 + 5n = 0


5n = –7


n =


The number of terms cannot be negative


Hence, the no term of A.P can be 0


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