Answer :

The mid–point of diagonals AC and diagonal BD coincide.

Thus, Section Formula internally =

Where l = 1 and m = 1

__Mid–point of diagonal AC__

A (1, 0) and C (2, 7)

The mid–point of diagonal is in the ratio of 1:1

=

=

=

__Mid–point of diagonal AC__

B (5, 3) and D (–2, 4)

The mid–point of diagonal is in the ratio of 1:1

=

=

=

Two diagonals are meeting at the same point. So, the given vertex forms a parallelogram.

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