Answer :

Formula Used.


dn = an + 1 – an


an = a + (n–1)d


In the above sequence,


a = 1000;


d1 = a2–a1 = 900–1000 = –100


d2 = a3–a2 = 800–900 = –100


The difference in sequence is same and comes to be (–100).


The above sequence is A.P


The nth term of A.P is an = a + (n–1)d


an = a + (n–1)d = 1000 + (n–1)(–100)


= 1000–100n + 100


= 1100–100n


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