Answer :

Formula Used.


dn = an + 1 – an


an = a + (n–1)d


In the above sequence,


a = 2;


d1 = a2–a1 = 7–2 = 5


d2 = a3–a2 = 12–7 = 5


d3 = a4–a3 = 17–12 = 5


The difference in sequence is same and comes to be 5 .


The above sequence is A.P


The nth term of A.P is an = a + (n–1)d


an = a + (n–1)d = 2 + (n–1)(5)


= 2 + 5n–5


= –3 + 5n


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arithmetic Progression- Don't miss these QuestionsArithmetic Progression- Don't miss these QuestionsArithmetic Progression- Don't miss these Questions56 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

In an A.P. 5th teGujarat Board Mathematics

Which term of A.PGujarat Board Mathematics

If in an A.P., T<Gujarat Board Mathematics

If in an A.P., T<Gujarat Board Mathematics

Find the 10th terGujarat Board Mathematics

Which term of A.PGujarat Board Mathematics

Can any term of AGujarat Board Mathematics

If for A.P., T<suGujarat Board Mathematics

For A.P. T18Gujarat Board Mathematics

Find the nth termGujarat Board Mathematics