Given,7(x – 2y)2 – 25 (x – 2y) + 12Let a = (x – 2y),So we have,= 7a2 – 25a + 12= 7a2 – 21a – 4a + 12= 7a(a - 3) -4 (a - 3)= (7a – 4) (a - 3)Put a = (x – 2y)= {7(x – 2y) – 4} (x – 2y - 3)= (7x – 14y -4) (x – 2y - 3)

Q. 323.8( 19 Votes )

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Class 9th RD Sharma - Mathematics 5. Factorization of Algebraic Expressions

Answer :

Given,

7(x – 2y)² – 25 (x – 2y) + 12

Let a = (x – 2y),

So we have,

= 7a² – 25a + 12

= 7a² – 21a – 4a + 12

= 7a(a - 3) -4 (a - 3)

= (7a – 4) (a - 3)

Put a = (x – 2y)

= {7(x – 2y) – 4} (x – 2y - 3)

= (7x – 14y -4) (x – 2y - 3)

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