# For the following APs, write the first term and the common difference:(i) (ii) (iii) (iv) (i) Here, first term a = 3

Now,

The Common difference of the A.P. can be calculated as:

a4 – a3

= - 3 – ( -1)

= - 3 + 1

= - 2

a3 – a2

= - 1 – 1

= - 2

a2 – a1

= 1 – 3

= - 2

Now, here ak+1 – ak = - 2 for all values of k

Hence, first term = 3 and common difference = - 2

(ii) a4 – a3

= 7 – 3

= 4

a3 – a2

= 3 – (-1)

= 3 + 1

= 4

a2 – a1

= - 1 – (-5)

= - 1 + 5

= 4

Now, here, ak+1 – ak = 4 for all values of k

Therefore, first term = - 5 and common difference = 4

(iii) From the question,

a4 – a3

=  a3 – a2

=  a2 – a1

= Now, ak+1 – ak for all values of k

Therefore,

First term = 1/3 and common difference = 4/3

(iv) a4 – a3

= 3.9 – 2.8

= 1.1

a3 – a2

= 2.8 – 1.7

= 1.1

a2 – a1

= 1.7 – 0.6

= 1.1

Now, here, ak+1 – ak = 1.1 for all values of k

Therefore,

First term = 0.6 and common difference = 1.1

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