Q. 2 H5.0( 2 Votes )

# Determine if the

Answer :

Formula Used.

dn = an + 1 – an

an = a + (n–1)d

The sequence of natural numbers which are consecutive multiples of 5

Is 5, 10, 15, 20 ……

In the above sequence,

a = 5;

d1 = a2–a1 = 10–5 = 5

d2 = a3–a2 = 15–10 = 5

d3 = a4–a3 = 20–15 = 5

As in A.P the difference between the 2 terms is always constant

The difference in sequence is same and comes to be 5.

The above sequence is A.P

The nth term of A.P is an = a + (n–1)d

an = a + (n–1)d = 5 + (n–1)5

= 5 + 5n–5

= 5n

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