Q. 2 G5.0( 2 Votes )

# Determine if the

Formula Used.

dn = an + 1 – an

an = a + (n–1)d

In the above sequence,

a = 201;

d1 = a2–a1 = 198–201 = –3

d2 = a3–a2 = 195–198 = –3

d3 = a4–a3 = 192–195 = –3

As in A.P the difference between the 2 terms is always constant

The difference in sequence is same and comes to be (–3).

The above sequence is A.P

The nth term of A.P is an = a + (n–1)d

an = a + (n–1)d = 201 + (n–1)(–3)

= 201–3n + 3

= 204–3n

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