Determine if the

Formula Used.

d_n = a_{n + 1} – a_n

a_n = a + (n–1)d

In the above sequence,

a = 17;

d₁ = a₂–a₁ = 22–17 = 5

d₂ = a₃–a₂ = 27–22 = 5

d₃ = a₄–a₃ = 32–27 = 5

⇒ As in A.P the difference between the 2 terms is always constant

The difference in sequence is same and comes to be 5.

∴ The above sequence is A.P

The n^th term of A.P is a_n = a + (n–1)d

a_n = a + (n–1)d = 17 + (n–1)5

= 17 + 5n–5

= 12 + 5n