Q. 2 E5.0( 2 Votes )

# Determine if the

Formula Used.

dn = an + 1 – an

an = a + (n–1)d

In the above sequence,

a = 17;

d1 = a2–a1 = 22–17 = 5

d2 = a3–a2 = 27–22 = 5

d3 = a4–a3 = 32–27 = 5

As in A.P the difference between the 2 terms is always constant

The difference in sequence is same and comes to be 5.

The above sequence is A.P

The nth term of A.P is an = a + (n–1)d

an = a + (n–1)d = 17 + (n–1)5

= 17 + 5n–5

= 12 + 5n

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