Q. 20

Is the function defined by f (x) = x2 – sin x + 5 continuous at x = π?

It is given that f (x) = x2 – sin x + 5

We know that f is defined at x = π

So, at x = π,

f(x) = f(π) = π2 -sin π + 5 = π2 – 0 + 5 = π2 + 5

Now,

Let put x = π + h

If

Thus,

Therefore, the function f is continuous at x = π.

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