Answer :

Formula Used.


an = a + (n–1)d


If a = 1000, d = –100


Then;


a1 = a + (n–1)d = 1000 + (1–1)(–100) = 1000


a2 = a + (n–1)d = 1000 + (2–1)(–100) = 1000 + (–100)×1 = 900


a3 = a + (n–1)d = 1000 + (3–1)(–100) = 1000 + (–100)×2 = 800


a4 = a + (n–1)d = 1000 + (4–1)(–100) = 1000 + (–100)×3 = 700


an = a + (n–1)d = 1000 + (n–1)(–100) = 1100–100n


The A.P is 1000, 900, 800, 700……, 1100–100n


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