Q. 1 E5.0( 2 Votes )

# Given a and d for

Formula Used.

an = a + (n–1)d

If a = 1000, d = –100

Then;

a1 = a + (n–1)d = 1000 + (1–1)(–100) = 1000

a2 = a + (n–1)d = 1000 + (2–1)(–100) = 1000 + (–100)×1 = 900

a3 = a + (n–1)d = 1000 + (3–1)(–100) = 1000 + (–100)×2 = 800

a4 = a + (n–1)d = 1000 + (4–1)(–100) = 1000 + (–100)×3 = 700

an = a + (n–1)d = 1000 + (n–1)(–100) = 1100–100n

The A.P is 1000, 900, 800, 700……, 1100–100n

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