(x - 3)(2x + 1) = x(x + 5)Here LHS = (x - 3)(2x + 1) = 2x2 - 6x + x - 3 = 2x2 - 5x - 3RHS = x(x + 5) = x2 + 5xEquating LHS and RHS2x2 - 5x - 3 = x2 + 5xx2 - 10x - 3 = 0 which is of the form ax2 + bx + c = 0∴ it is a quadratic equation.

Q. 1 D5.0( 6 Votes )

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Class 10th AP- Mathematics 5. Quadratic Equations

Answer :

(x - 3)(2x + 1) = x(x + 5)

Here LHS = (x - 3)(2x + 1) = 2x² - 6x + x - 3 = 2x² - 5x - 3

RHS = x(x + 5) = x² + 5x

Equating LHS and RHS

2x² - 5x - 3 = x² + 5x

x² - 10x - 3 = 0 which is of the form ax² + bx + c = 0

∴ it is a quadratic equation.

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