Answer :

Formula Used.


an = a + (n–1)d


If a = –3, d = –2


Then a1 = a + (n–1)d = –3 + (1–1)(–2) = –3


a2 = a + (n–1)d = –3 + (2–1)(–2) = –3 + 1×(–2) = –5


a3 = a + (n–1)d = –3 + (3–1)(–2) = –3 + 2×(–2) = –7


a4 = a + (n–1)d = –3 + (4–1)(–2) = –3 + 3×(–2) = –9


an = a + (n–1)d = –3 + (n–1)(–2) = –1–2n


The A.P is –3, –5, –7, –9……, –1–2n


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