Answer :

Formula Used.


an = a + (n–1)d


If a = 3, d = 2


Then a1 = a + (n–1)d = 3 + (1–1)2 = 3


a2 = a + (n–1)d = 3 + (2–1)2 = 3 + 2×1 = 5


a3 = a + (n–1)d = 3 + (3–1)2 = 3 + 2×2 = 7


a4 = a + (n–1)d = 3 + (4–1)2 = 3 + 2×3 = 9


an = a + (n–1)d = 3 + (n–1)2 = 2n + 1


The A.P is 3, 5, 7, 9……, 2n + 1


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