Q. 1 A5.0( 3 Votes )

# Given a and d for

Formula Used.

an = a + (n–1)d

If a = 3, d = 2

Then a1 = a + (n–1)d = 3 + (1–1)2 = 3

a2 = a + (n–1)d = 3 + (2–1)2 = 3 + 2×1 = 5

a3 = a + (n–1)d = 3 + (3–1)2 = 3 + 2×2 = 7

a4 = a + (n–1)d = 3 + (4–1)2 = 3 + 2×3 = 9

an = a + (n–1)d = 3 + (n–1)2 = 2n + 1

The A.P is 3, 5, 7, 9……, 2n + 1

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