Q. 163.9( 11 Votes )
The sum of first 16 terms of the AP 10, 6, 2, ….. is
A. - 320
B. 320
C. - 352
D. - 400
Answer :
Given,
First term, a = 10
Common Difference, d = 6 - 10 = - 4(a2 - a1)
Using the formula,
Where Sn is the sum of first n terms
n = no of terms
a = first term
d = common difference
S16 = (16/2)[ 2(10) + (16 - 1) (- 4)]
= 8(20 - 60)
= - 320
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The sum of n terms of an A.P. is 3n2+ 5n. Find the A.P. Hence, find its 16th term.
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