Q. 163.9( 11 Votes )

# The sum of first 16 terms of the AP 10, 6, 2, ….. is

A. - 320

B. 320

C. - 352

D. - 400

Answer :

Given,

First term, a = 10

Common Difference, d = 6 - 10 = - 4(a_{2} - a_{1})

Using the formula,

Where S_{n} is the sum of first n terms

n = no of terms

a = first term

d = common difference

S_{16} = (16/2)[ 2(10) + (16 - 1) (- 4)]

= 8(20 - 60)

= - 320

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Champ Quiz | Arithmetic Progression34 mins

Smart Revision | Arithmetic Progression47 mins

Champ Quiz | Arithmetic Progression30 mins

Quiz | Arithmetic Progression44 mins

NCERT | Fundamental Theorem Of Arithmetic45 mins

Smart Revision | General Term of an A.P44 mins

Lets Check Your Knowledge in A.P.49 mins

Quiz on Arithmetic Progression Quiz32 mins

NCERT | Arithmetic Progression36 mins

Get to Know About Geometric Progression41 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

The sum of n terms of an A.P. is 3n^{2}+ 5n. Find the A.P. Hence, find its 16th term.