Answer :

Given: radius of a circle = 5cm

Distance of chord from centre = 4cm

By, Given information we will draw a circle

Given, radius PB = 5cm

PC = 4cm where, P is perpendicular bisector of segAB

Thus, ∠PCB = 90°

By Pythagoras formula

PB^{2} = BC^{2} + PC^{2}

5^{2} = BC^{2} + 4^{2}

25 = BC^{2} + 16

BC^{2} = 25 - 16 = 9cm

BC = √9 = 3cm

Since, P is perpendicular bisector of seg AB

Therefore, BC = CA = 3cm

Therefore, BA = BC + CA

BA = 3 + 3 = 6cm

Thus, length of a chord BA = 6cm

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