# The radius of a c

Given: radius of a circle = 5cm

Distance of chord from centre = 4cm

By, Given information we will draw a circle

PC = 4cm where, P is perpendicular bisector of segAB

Thus, PCB = 90°

By Pythagoras formula

PB2 = BC2 + PC2

52 = BC2 + 42

25 = BC2 + 16

BC2 = 25 - 16 = 9cm

BC = √9 = 3cm

Since, P is perpendicular bisector of seg AB

Therefore, BC = CA = 3cm

Therefore, BA = BC + CA

BA = 3 + 3 = 6cm

Thus, length of a chord BA = 6cm

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