Q. 2

# In the figure, <s

Given: seg 0M seg AB

That is OMB = OMA = 90°

seg AM = 1.5cm

Join OA and OB, we get,

Now in ∆OMA and ∆OMB

OMB = OMA = 90° (since, seg 0Mseg AB )

seg OA = seg OB (since, OA and OB are radius of a circle)

seg OM = seg OM (since, common side)

Therefore, ∆OMA OMB (By, RHS Congruent Rule)

Therefore, seg AM = seg BM (By CPCT)

Thus, seg AM = seg BM = 1.5cm

seg AB = seg AM + seg BM

seg AB = 1.5 + 1.5 = 3cm

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