Answer :

Given: seg 0M seg AB

That is OMB = OMA = 90°


seg AM = 1.5cm


Join OA and OB, we get,



Now in ∆OMA and ∆OMB


OMB = OMA = 90° (since, seg 0Mseg AB )


seg OA = seg OB (since, OA and OB are radius of a circle)


seg OM = seg OM (since, common side)


Therefore, ∆OMA OMB (By, RHS Congruent Rule)


Therefore, seg AM = seg BM (By CPCT)


Thus, seg AM = seg BM = 1.5cm


seg AB = seg AM + seg BM


seg AB = 1.5 + 1.5 = 3cm


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