Answer :

We have, f(x) = |2x – 1| sinx


Now, 2x-1 = 0



Now we will check the differentiability of f(x) at 1/2.



=


= ( f(x) = |2x – 1| sinx)


=


=


=



=


= ( f(x) = |2x – 1| sinx)


=


=


=



Hence, f(x) is not differentiable at

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