Answer :
For given AP,
First term, a = 1
Common difference, d = a2 – a
= 8 – 1
= 7
Let the number of terms be n, then
Last term, an = 505
We know, nth term of an AP is
an = a + (n – 1)d
⇒ 505 = 1 + (n – 1)7
⇒ 504 = 7(n – 1)
⇒ n – 1 = 72
⇒ n = 73
Also,
a37 = a + 36d
= 1 + 36(7)
= 1 + 252
= 253
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