Q. 27

In Fig. 5.23, if A. 40°

B. 30°

C. 90°

D. 80°

Answer :


We draw an imaginary straight line UT ||QP || SR


UTS = TSR = 30° (Alternate Interior angle)


UTQ = TQP = 60° (Alternate Interior angle)


a = UTQ + UTS


a = 60° + 30° = 90°

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