Q. 263.7( 3 Votes )

In Fig. 5.22, the A. 20°

B. 15°

C. 5°

D. 10°

Answer :

Let the point of intersection of all the three lines be O


AOF = COD = 90°


BOC, COD and DOE forms a linear pair


Since COD = 90°


So BOC and DOE are complementary angles


40° + 5a = 90°


5a = 50°


a = 10°

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