Q. 263.7( 3 Votes )
In Fig. 5.22, the A. 20°
B. 15°
C. 5°
D. 10°
Answer :
Let the point of intersection of all the three lines be O
∠ AOF = ∠ COD = 90°
∠ BOC, ∠ COD and ∠ DOE forms a linear pair
Since ∠ COD = 90°
So ∠ BOC and ∠ DOE are complementary angles
40° + 5a = 90°
⇒ 5a = 50°
⇒ a = 10°
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