Answer :

Let z1 = x1 + iy1 and z2 = x2 + iy2


z1 + z2 = (x1 + x2) + i (y1 + y2) which is real


y1 + y2 = 0


y1 = - y2


Assuming x1 = x2


Since z2 = x1 – iy1


z2 = z̅ 1


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